Idanwo ti o sopọ mọ itọsọna · Alabọde Ipele

Adanwo Awọn iṣẹ Isonu

Test prediction objectives, squared and absolute errors, class cross-entropy, usable training derivatives, loss units, and numerical error averages.

Jẹmọ itọsọna awọn ọnaAwọn iṣẹ pipadanu
Ibeere 1 ti 8

For a prediction task, what does its selected loss quantify against the training target?

Awotẹlẹ gbogbo ibeere8 ibeere

Awọn idahun ati awọn alaye han bi o ṣe n mu ibeere naa.

  1. For a prediction task, what does its selected loss quantify against the training target?
    • A specified prediction-error objective
    • Only runtime speed
    • Only the number of network layers
    • Every application benefit automatically
  2. Iṣẹ ipadanu wo ni a lo julọ fun awọn iṣẹ ṣiṣe isọdi?
    • Aṣiṣe onigun mẹrin tumọ si
    • Itumọ aṣiṣe pipe
    • Cross-entropy pipadanu
    • Ijinna mitari nikan
  3. Ti a ṣe afiwe si tumọ si aṣiṣe onigun mẹrin, kilode ti o le yan tumọ si aṣiṣe pipe?
    • O ṣe iyipo awọn aṣiṣe lati jẹ wọn ni iya diẹ sii
    • O ti wa ni diẹ logan to outliers nitori ti o ko ni square awọn aṣiṣe
    • Ko le ṣee lo fun ipadasẹhin
    • O foju awọn aami otitọ
  4. Why does gradient-based training need a usable loss derivative or suitable substitute?
    • So a loss number can be printed
    • So all learning methods become identical
    • So the dataset no longer needs targets
    • So backpropagation and optimization can obtain an update signal
  5. How does one-hot class cross-entropy change as probability assigned to the target class becomes very small?
    • Its loss must become zero
    • It rewards the prediction increasingly
    • Its loss becomes large
    • It becomes identical to accuracy
  6. Kini idi ti deede kii ṣe lo taara bi pipadanu ikẹkọ?
    • Ko ṣe iyatọ, nitorinaa ko fun gradient ti o wulo
    • O rọrun pupọ lati ṣe iṣiro
    • O ṣiṣẹ nikan fun ipadasẹhin
    • O nigbagbogbo dogba pipadanu naa lonakona
  7. For illustrative regression residuals one and three, what are mean squared error and mean absolute error?
    • MSE is two and MAE is five
    • Both are four
    • MSE is ten and MAE is four
    • MSE is five and MAE is two
  8. Using a base-two logarithm, what one-hot cross-entropy loss corresponds to target-class probability one-quarter?
    • One-quarter bit
    • Two bits
    • Four bits
    • Zero bits