quiz bu lëkkale ak tegtal · Diggante Niveau

Quiz moyenne de poids stochastique

Saytu SWA diisaayu moyenne, jàng-taux jeffin, recalibration lots-normalisation ak ni benn model moyenne di wuutee ak ensemble.

Yooni njiit yu jëm ciStochastic moyenne poids
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Lan mooy moyenne poids stochastic ci dëgg?

Xoolaatal laaj bu nekk8 laaj

Sooy def quiz bi, tontu yi ak leeral yi dañuy feeñ.

  1. Lan mooy moyenne poids stochastic ci dëgg?
    • Diisaayu model bi ñu jël ci poñ yu bari ci diggu tàggat yaram
    • Xalaatal yu bari ci xeetu model yuñ tàggat bu wuute
    • degrade yi ñu xayma ci lote yu ndaw yépp
    • Tolluwaayu jàng yi ñuy jëfandikoo ci jamono bu nekk
  2. Lan moo waral SWA di gëna suqali généralisasioŋ bi?
    • Dafay gëna xam tàggat yaram bi
    • Dafay gis minima yu gëna yaatu, gëna plat yu gëna dëgër ci done yuñu gisul
    • Dafay yokk limu parametre yi ci model bi
    • Dafay dindi soxla ensemble validation
  3. Ban jéego bu gëna am solo la SWA soxla ci reso yiy jëfandikoo normalisasioŋ ci lots?
    • Taggaat reso bi ci noonu
    • Ñaari yoon yokk dayo lote bi
    • Beneen paas ngir xaymawaat lim yi BN di daw
    • Di dindi bépp couche dropout
  4. Ban jeffin juy jàng mooy gëna bari luñu koy jëfandikoo ci wàllu moyenne SWA?
    • Tolluwaayu jàng daa wàññeeku ba amul dara
    • Njàngat bu benn ngir dakkal
    • Amul benn njàng ndax dañu tëj tàggat yaram
    • Tolluwaayu jàng bu sax wala buy wëréelu
  5. Lan mooy njëgu inference bu SWA buñu ko méngale ak ensemble bu cosaan bu N models?
    • Lu tollu ci benn xeetu njëg la, ndax limuy génne mooy benn xeetu poid
    • Dafa seer N yoon
    • Dafay nuru ak daw model N
    • Mënu ñu ko jëfandikoo ngir def ay tegtal
  6. Why does the batch-normalization adjustment belong after SWA weight averaging?
    • The averaging step deletes every convolution
    • Its running statistics must be recomputed for the averaged weights
    • It converts batch normalization into layer normalization
    • It restores the original optimizer learning rate
  7. An SWA running mean combines n previous samples with a new weight vector w_i. Which update gives equal weight to all n+1 samples?
    • w_SWA + n · w_i
    • (w_SWA + w_i) divided by n
    • (n · w_SWA + w_i) divided by (n + 1)
    • n · (w_SWA − w_i)
  8. Why is SWA commonly started during the later part of training?
    • It requires the model to remain at random initialization
    • It can only average models with different architectures
    • It replaces the training data with validation examples
    • It averages nearby useful checkpoints from a trajectory after the model has made substantial progress