Guide-linked quiz · Medium Level
Learning Rate Scheduling Quiz
Checks warmup, cosine and step schedules, restart behavior, early instability and the common warmup-then-decay training recipe.
Question 1 of 8
What is the purpose of a 'warmup' phase in a learning rate schedule?
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Answers and explanations appear as you take the quiz.
- What is the purpose of a 'warmup' phase in a learning rate schedule?
- To start with a small rate and ramp up, avoiding instability from early noisy gradients
- To make the final accuracy lower
- To skip the first few batches of data
- To freeze all the weights at the start
- Which schedule smoothly follows a half-cosine curve down toward a minimum rate?
- Constant schedule
- Cosine annealing
- Random schedule
- Linear increase
- What happens if the learning rate is set far too high?
- Training converges instantly with perfect accuracy
- The model trains slower but always succeeds
- The loss can diverge or oscillate instead of decreasing
- Nothing changes; the rate has no effect
- What does step decay do to the learning rate?
- Increases it linearly every batch
- Keeps it perfectly constant
- Sets it randomly each step
- Drops it by a fixed factor at predefined epochs
- What does a warm restart do to a learning-rate schedule?
- It raises the learning rate again to begin another schedule cycle
- It resets the model parameters to random values
- It permanently fixes the learning rate at zero
- It deletes the optimizer’s moment estimates
- In Goyal et al.’s large-minibatch ImageNet setup, what did their warmup scheme address?
- It removed the need for a validation set
- It eased early optimization difficulties after the learning-rate scale increased with batch size
- It changed the model architecture after each epoch
- It converted the learning-rate curve into a cosine wave
- In the cosine formula, what does T denote?
- The number of model layers
- The batch size
- The schedule horizon or total number of steps used for the decay
- The optimizer’s momentum coefficient
- If the cosine schedule uses lr_min greater than zero, where does the rate approach at the end of the horizon?
- Exactly zero regardless of lr_min
- The original warmup starting rate
- An unbounded value
- The specified minimum learning rate
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