Guide-linked quiz · Medium Level
Spectral Clustering Quiz
Trace spectral clustering from affinity graph to Laplacian embedding and examine how graph construction and label assignment affect clusters.
Question 1 of 8
Which representation does spectral clustering commonly construct before computing a Laplacian?
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Answers and explanations appear as you take the quiz.
- Which representation does spectral clustering commonly construct before computing a Laplacian?
- A similarity or affinity graph
- A decision tree of class labels
- A density histogram with fixed bins
- A linear regression residual matrix
- Why can spectral clustering help with nested-ring data?
- It turns rings into normally distributed classes automatically
- Graph connectivity can represent non-convex groups beyond centroid partitions
- It always selects two clusters without user input
- It removes the need to define similarity
- What role do selected Laplacian eigenvectors play?
- They set all pairwise distances to zero
- They are the original class labels
- They form an embedding used for subsequent cluster assignment
- They estimate the number of observations
- What may happen if an affinity graph is too sparse?
- All observations receive equal similarity
- Every region becomes one connected component
- The graph becomes an RBF kernel automatically
- A true group may break into disconnected fragments
- Why can the final labels vary even with the same embedding?
- Eigenvectors contain the true semantic names
- The label-assignment step has its own choices and initialization
- Every labeling method is mathematically identical
- The affinity matrix becomes asymmetric
- What does a graph degree represent in the Laplacian construction?
- The coordinate's squared distance from zero
- The number of clusters supplied
- The sum of an observation's edge weights
- The eigenvector's class probability
- How does an RBF kernel width affect graph affinities?
- It changes the response variable's units
- It sets the true number of clusters
- It guarantees a connected graph
- It controls how quickly similarity decreases with distance
- Why should a disconnected graph be examined before interpreting spectral labels?
- The normalized-cut result may not match the intended connected-cluster interpretation
- It proves all clusters are invalid
- Disconnected graphs cannot have eigenvectors
- It means every point has an identical affinity
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